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X= 0,1 x 6,02.10^23
X= 6,02.10^22 molekul
massa=n.Mr
massa= 0,1 . 44= 4,4gram
volume jika tidak ada kondisi =STP
Vstp=n.22,4
Vstp= 0,1 . 22,4= 2,24L
massa = 0,1x44
massa=4,4 gr
Jumlah partikel = n x 6,02x10²³
Jumlah partikel = 0,1 x 6,02 x 10²³ = 6,02 x10²²
V= n x 22,4
V=0,1 x 22,4 = 2,24 liter