1.Jaką objętość ma kula o powierzchni 16 ?
2.Oblicz objętość i pole całkowite czworościanu foremnego o krawędzi 5cm.
z.1
P = 16 pi m^2
oraz
P = 4 pi *r^2
zatem
4 pi* r^2 = 16 pi m^2 / : 4 pi
r^2 = 4 m^2
r = 2 m
==========
Objętość kuli
V = (4/3) pi *r^3
czyli
V = (4/3) pi * 2^3 = (4/3) *8 pi = (32/3) pi
Odp. V = (32/3) pi m^3
============================
z.2
a = 5 cm
V = [ a^3 * p(2)] /12
V = [ 5^3 * p(2)]/12 = (125/12) * p(2)
Odp. V = (125/12) p(2) cm^3
==============================
Pc = a^2 * p(3) = 5^2 * p(3) = 25 p(3)
Odp. Pc = 25 p(3) cm^2
=======================
1)
P=16π m²
4πr² = 16π
4r² = 16
r² = 4
r= 2m
2)
a=5cm
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z.1
P = 16 pi m^2
oraz
P = 4 pi *r^2
zatem
4 pi* r^2 = 16 pi m^2 / : 4 pi
r^2 = 4 m^2
r = 2 m
==========
Objętość kuli
V = (4/3) pi *r^3
czyli
V = (4/3) pi * 2^3 = (4/3) *8 pi = (32/3) pi
Odp. V = (32/3) pi m^3
============================
z.2
a = 5 cm
V = [ a^3 * p(2)] /12
V = [ 5^3 * p(2)]/12 = (125/12) * p(2)
Odp. V = (125/12) p(2) cm^3
==============================
Pc = a^2 * p(3) = 5^2 * p(3) = 25 p(3)
Odp. Pc = 25 p(3) cm^2
=======================
1)
P=16π m²
4πr² = 16π
4r² = 16
r² = 4
r= 2m
2)
a=5cm