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a) ~ f(-3) = -3(-3) +6
= 9 +6
= 15
~ f(x) = -3x+6
f(2) = -3(2) + 6
= -6 +6
= 0
b) f(x)=-3x+6
f(x)= -9
-3x+6 = -9
-3x = -9 - 6
-3x = -15
x = -15
-3
x = 5
2. Daerah asal (domain) = A={6,8,10,12}
rumus fungsi f(x)=3x-4
tentukan: f(6), f(8), f(10), f(12).
⇒ f(6) = 3(6) - 4
= 18 -4
= 14
⇒ f(8) = 3 (8) -4
= 24 - 4
= 20
⇒ f(10) = 3(10) -4
= 30 - 4
= 26
⇒ f(12) = 3(12) - 4
= 36 -4
= 32