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2πr*75=3πr²
150πr=3πr² |:3π
50r=r² |:r
r=50
Pb - pole powierzchni bocznej = 2πr razy 75 = 150πr cm²
Pp - pole podstawy walca = πr²
z warunków zadania
3Pp = Pb
3πr² = 150πr
150πr/πr² = 3
150/r = 3
150 = 3r
r = 150/3 = 50 cm
odp
r - promień podstawy = 50 cm