Question

√2*√4½

√2⅔ /⅔

√6,4 / √10

∛10*∛0,1

∛2⅔*∛jedna dziewiata

∛2,7 /∛100

∛-9*∛3

∛128/∛-2

∛-0,5*∛4 /∛16

to jest z działan na pierwiastkach bardzo prosze o odp musze miec to na dzisiaj Prosze

Answer 1

√2*√4½ =

= √2*√(9/2) =

=√2*3 :√2 =

= 3

 

√2⅔ /⅔ =

= √(8/3) : 2/3 =

= 2√2 :√3 : 2/3 =

= [2√2 :√3 ]*3/2=

=[ 2√2 :√3*3/2]=

= [(3√2) :√3]*[√3 : √3] =

= (3√2):3 =

= √2

 

√6,4 / √10=

=√(64/10) : √10 =

= [√64 :√10] :√10 =

= [ 8 : √10 ] *1/√10 =

= 8/10 =

= 0,8

 

∛10*∛0,1=

=∛10*∛(1/10)=

=∛10:∛10 =

= 1

 

∛2⅔*∛jedna dziewiata

= ∛2⅔*∛(1/9)=

= ∛(8/3)*∛(1/9)=

=(∛8 ) : (∛27) =

= 2 : 3 =

= 2/3

 

∛2,7 /∛100=

=∛(27/10) :∛100=

= (∛27) : :∛10*∛100=

= 3 :∛1000 =

= 3 : 10=

= 0,3

 

∛-9*∛3=

= ∛(-27)= -3

 

∛128/∛-2 =

= ∛64 *∛2 : ∛(-2) =

=[  4∛2 ] : ∛(-2) =

= - 4 ∛2 : ∛2 =

= - 4

 

∛-0,5*∛4 /∛16=

=∛(-1/2)*∛4 : ∛16 =

= [∛(-1) : ∛2]*∛4 : (∛16)=

= [-1*∛2*∛2] : [*∛2 *∛16] =

= [-∛2] : [∛16 ] =

= [-∛2] : [ 2∛2] =

= - 1/2