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a) 12+ (a+8)+(3a-3)=49
12+a+8+3a-3=49
17+4a=49
b)5+4b+3b+4+4b-4+36-5=49
146=49
c) P(trapezu)= (a+b)*h /2
P(trapezu)= (8+2c+8)*10 /2 [skróć 10 z 2]
P(trapezu)= 40+10c+40
120=80+10c
d) P(rombu)= e*f /2
96= 12*2d / 2 [skróć 12 i 2]
96= 6 *2d
96=12d
Mam nadzieję że pomogłam! :*