Question

zadanie 1 . ułamki :)P

a)

( 1/18 - 0,3 ) * ( 1i 1/6 + 1/12)

b) 2 i 1/3 * (5/14- 2/35) - (2,3 - 1 i 3/20 )

c) [( 1/16+ 3/20) - (13/40- 0,4)] : ( 1i11/20+19)

d) ( 13/24 - 7/18) : [(9/16 - 5/24) - (5/12 - 1 i 7/16 ) ]

Answer 1

(1/18-0,3)*(1 1/6+1/12)=1/18- 3/10*1 2/12+1/12=5/90-27/90*1 3/12= -22/90*5/4=-110/360=-11/36

2 1/3 * (5/14-2/35)-(2,3-1 3/20)= 7/6*(10/70-4/70)-(46/20-23/20)=7/6* 6/70-(-23/20)=42/420+23/20=2/20+23/20=25/20=1 5/20= 1 1/4

[(1/16+3/20)-(13/40-4/10)]:(1 11/20+19)= [(5/80+12/80)-(13/40-16/40)]:20 11/20=(17/80- (-3/40)]:411/20=(17/80+6/80):411/20= 23/80*20/411=23/1644

(13/24-7/18):[(9/16-5/24)-(5/12-1 7/16)]=39/72-28/72:[(27/48-10/48)-(20/48-69/48)]=11/72:[17/48-(-49/48)]=72/11*17/48+49/48=72/11*66/48=4752/528=9