Zad 6/142 1 gim. Matematyka Wokół Nas
a). (√17)²-(√24)²
b). (-2)·(√5)²+√1
c). (√⅓)²·√(⅕·⅕)
zad
a)(√17)²-(√24)² = 17-24=-7
b)(-2) · (√5)² +√1= (-2·5)+1=- 10+1= -9
c)(√⅓)² · √(⅕·⅕) = ⅓·√¹/₂₅ = ⅓·⅕ = ¹/₁₅
a). (√17)²-(√24)²=17-24=-7
b). (-2)·(√5)²+√1=(-2)*5+1=-10+1=-9
c). (√⅓)²·√(⅕·⅕)=⅓ * √¹/₂₅ = ⅓ * ⅕ = ¹/₁₅
Pozdrawiam ;)
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zad
a)(√17)²-(√24)² = 17-24=-7
b)(-2) · (√5)² +√1= (-2·5)+1=- 10+1= -9
c)(√⅓)² · √(⅕·⅕) = ⅓·√¹/₂₅ = ⅓·⅕ = ¹/₁₅
a). (√17)²-(√24)²=17-24=-7
b). (-2)·(√5)²+√1=(-2)*5+1=-10+1=-9
c). (√⅓)²·√(⅕·⅕)=⅓ * √¹/₂₅ = ⅓ * ⅕ = ¹/₁₅
Pozdrawiam ;)