Question

A) (1/8)⁻³÷(1/4)⁻³×6=
B) (-2⅔ )⁻² ÷ (8/3)⁻²+o,250⁰=
C) (3/14)⁻³× 7⁻³⁺27⁻¹=
D) (0,2)⁻¹₋(0,8)⁻¹×10⁻¹=
E) (6⅖)⁻⁴÷(6,4)⁻⁴₋2⁻⁴=

Answer 1

A) (1/8)⁻³÷(1/4)⁻³×6=8³÷4³*6=2⁹÷2⁶*×6=2³×6=8×6=48
B) (-2⅔ )⁻² ÷ (8/3)⁻²+o,250⁰=(-3/8)²÷(3/8)²+1=(-3/8÷3/8)²+1=(-1)²+1=2
C) (3/14)⁻³× 7⁻³⁺27⁻¹=(14/3)³×(1/7)³+(1/3)³=(14/3×1/7)³+(1/3)³=(2/3)³+1/27=8/27+1/27=9/27=1/3
D) (0,2)⁻¹₋(0,8)⁻¹×10⁻¹=10/2-10/8×1/10=5-1/8=4⅞
E) (6⅖)⁻⁴÷(6,4)⁻⁴₋2⁻⁴= (5/32)⁴÷(10/64)⁴-(1/2)⁴=(5/32÷10/64)⁴-1/16=(5/32×64/10)⁴-1/16=1-1/16=15/16