Question

Diketahui cos A = 4/5 dan sin B = 5/13' sudut A dan B keduanya lancip. Hitunglah nilai berikut:?
a. Sin A
b. Cos B
c. Tan A
d. Tan B
Jwab dengan caranya

Answer 1

Cos A = 4/5
cos = samping/miring
samping= 4
miring = 5
depan = √5² - 4²
= √25-16
= √9
= 3

a. sin A = depan/miring
= 3/5

C. tan A = depan/samping
= 3/4

sin B = 5/13
sin = depan/miring
depan = 5
miring = 13
samping = √13² - 5²
= √169-25
= √144
= 12

B. cos B = samping/miring
= 12/13

D. tan B = depan/samping
= 5/12