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= x^2 +2
kedua (3x-5)
=3/2 x^2 -5
lalu masukan angka angka tadi
= [(0)^2 +2]+[(2)^2] +[ 3/2 (0)]^2-5] - [3/2(2)^2-5]
= 2+4+(-5)-6-5
= -10
= x^2 +2
kedua (3x-5)
=3/2 x^2 -5
lalu masukan angka angka tadi
= [(0)^2 +2]+[(2)^2] +[ 3/2 (0)]^2-5] - [3/2(2)^2-5]
= 2+4+(-5)-6-5
= -10