October 2018 1 102 Report

1) 7¹²×3+4×7¹³

------------=

(7¹²÷7⁸)³

2) √32+√72-√50=

3) (3⁻²)⁻³÷3⁸=

4) (1i5/11)⁻²÷(4/11)⁻²=

5/11; 4/11 to są ułamki, tzn. (⅔)


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