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g(x+3)=2x+5
g(x) = 2(x-3)+5
=2x-6+5
=2x-1
(hogof)-¹(x) = (-x-5) / 10
hogof dalam bentuk invers maka inverskan lagi supaya inversnya hilang
jadi
y = (-x-5) / 10
10y = -x-5
x = -10y-5
(hogof)(x) = -10x-5
f(x) =-x dan g(x) =2x-1
(ho(gof) (x)
(gof)(x) = 2(-x) -1=-2x-1
h(-2x-1)(x) = -10x-5
misal
t = -2x-1
2x=-t-1
x=-t-1 / 2
h(x) = -10(-t-1 / 2) -5
=-5(-t-1)-5
=5t+5-5
=5t
h(x) =5x
h(k) =-10
5k=-10
k=-10/5
k=-2
solved