Oblicz:
(2/3)-² - (4/3)-¹b.) [(⅕)⁻³ - (⅓)⁻⁴]⁻¹
c.) 4² · 4⁻¹ -7⁰ / 1+2⁻³
d.) (⅕)⁻³ · ⁵⁻² +(⅕)⁻² / 10 - (½) ⁻³
(2/3)-² - (4/3)-¹=(3/2)²-3/4=9/4-3/4=6/4=1 1/2b.) [(⅕)⁻³ - (⅓)⁻⁴]⁻¹=[5³-2⁴]⁻¹=125-16]⁻¹=109⁻¹=1/109c.) 4² · 4⁻¹ -7⁰ / 1+2⁻³=4-1/9/8=4-1*8/9=3 1/9d.) (⅕)⁻³ · ⁵⁻²? +(⅕)⁻² / 10 - (½) ⁻³-bakuje podstawy przy pytajniku
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(2/3)-² - (4/3)-¹=(3/2)²-3/4=9/4-3/4=6/4=1 1/2
b.) [(⅕)⁻³ - (⅓)⁻⁴]⁻¹=[5³-2⁴]⁻¹=125-16]⁻¹=109⁻¹=1/109
c.) 4² · 4⁻¹ -7⁰ / 1+2⁻³=4-1/9/8=4-1*8/9=3 1/9
d.) (⅕)⁻³ · ⁵⁻²? +(⅕)⁻² / 10 - (½) ⁻³-bakuje podstawy przy pytajniku