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P=a² - 1/2ba-1/2 a(a-b)-1/2b(a-b)
P=a² -1/2ab-1/2 a²+1/2ab-1/2 ab+1/2 b²
P=1/2 a² -1/2 ab +1/2 b²
P=1/2*5² -1/2*5*1 +1/2 *1²
P=25/2-5/2+1/2=12,5-2,5+1/2=10,5
2.oblicz pole narysowanego trapezu wiedząc,że 24ab+12b²=13
P=1/2(a+b+3a+b)*2b
P=1/2(4a+2b)*2b
P=4ab+2b² =13/6
24ab+12b²=13 /:6
4ab+2b²=13/6