Question

1. (x+3)kwadrat + 6(x+3)=16
2. (3x+2)(x-1)-13=2x(2-x)
3. 9(x-4)kwadrat + 4(x-4)=0
4. (y+3)(y+2)=1-y

Answer 1

(x+3)(x+3) +6x+18=16
x^2+3x+3x+9 +6x+18 -16 =0
x^2+12x-11=0
delta= b^2-4ac
d= 12^- 4*1*(-11)

d= 144+44
d = 188
d= pod pierwiastkiem 188


3x^2-3x+2x-2-14-4x-2x=0
3x ^2-7x-16=0
delta= b^2-4ac
d= 7^2- 4 * 3 * (-16)
d= 49+192
d= 241
d= 241 pod pierwiastkiem


9(x-4)(x+4) +4x -16=0
9 ( x^2 +4x-4x) +4x -16 = 0
9x^2 + 36x -36x + 4x - 16 = 0
9x^2 + 4x -16= 0

delta= 16 - 36 ( - 16 )
d=  592
d= 592 pod pierwiastkiem


y^2+2y+3y+6-1+y=o
y^2+6y -5 = 0

delta= 36 - 4 ( -20)
d=  2880
d= 2880 pod pierwiastkiem