1. wyrazenie cos A x tg A =?
2.w ciagu arytmetycznym drugi wyraz ciagu wynosi 7 a piaty 14 roznica tego ciagu to;?
1. cos A * tgA= cosA * (sinA/cosA)=sinA
2.a2= 7, a5=14, a5=a2 + 3r
14=2 + 3r
12=3r
r=4
1 cosA*tgA=cosA*sinA/cosA=sinA2 a2=7 a5=a2+3r14=7+3r7=3rr=7/3
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1. cos A * tgA= cosA * (sinA/cosA)=sinA
2.a2= 7, a5=14, a5=a2 + 3r
14=2 + 3r
12=3r
r=4
1 cosA*tgA=cosA*sinA/cosA=sinA
2 a2=7 a5=a2+3r
14=7+3r
7=3r
r=7/3