1 trapez o ramieniu dlugości 12 cm i 18 cm opisany jest na okręgu o promieniu 5 cm oblicz pole tego trapezu
c=12cm
d=18cm
r=5cm
h=wysokośc
a+b=c+d
a+b=12+18
a+b=30cm
pole=½r(a+b+c+d)=½×5(30+12+18)=2,5×60=150cm²
pole na trapez to (a+b)xh/2 = (12cm+18cm)x5cm / 2 = 75 cm
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c=12cm
d=18cm
r=5cm
h=wysokośc
a+b=c+d
a+b=12+18
a+b=30cm
pole=½r(a+b+c+d)=½×5(30+12+18)=2,5×60=150cm²
pole na trapez to (a+b)xh/2 = (12cm+18cm)x5cm / 2 = 75 cm