1. oblicz objętość walca o polu podstawy 81 pi cm 2 i polu powierzchni bocznej 270pi cm2
Pp = πr² = 81 π
r = 9
Pb = 2πrH = 270 π
135 = rH
h = 135/9 = 15
V = πr²H
V = π9²*H = 81π * 15 = 810 π + 405π = 1215 π cm³
πr²=81π
2πrH=270π
r²=81
2rH=270
r=9
18H=270
r=9 (cm)
H=15 (cm)
V=πr²H
V=π·(9cm)²·15cm=1215π cm³
Odp.: Objętość walca wynosi 1215π cm³.
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Pp = πr² = 81 π
r = 9
Pb = 2πrH = 270 π
135 = rH
h = 135/9 = 15
V = πr²H
V = π9²*H = 81π * 15 = 810 π + 405π = 1215 π cm³
πr²=81π
2πrH=270π
r²=81
2rH=270
r=9
18H=270
r=9 (cm)
H=15 (cm)
V=πr²H
V=π·(9cm)²·15cm=1215π cm³
Odp.: Objętość walca wynosi 1215π cm³.