" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
f(1) = a.1 + b
3 = a + b..........persamaan 1
f(x) = ax + b
f(2) = a.2 + b
5 = 2a + b..........persamaan 2
eliminasi : a + b = 3 | x 2 | 2a + 2b = 6
2a + b = 5 | x 1 | 2a + b = 5
------------------------- -
b = 1
a + b = 3
a + 1 = 3
a = 3 - 1
a = 2
f(x) = ax + b
f(x) = 2x + 1
f(1) = a.1 + b
3 = a + b..........persamaan 1
f(x) = ax + b
f(2) = a.2 + b
5 = 2a + b..........persamaan 2
eliminasi : a + b = 3 | x 2 | 2a + 2b = 6
2a + b = 5 | x 1 | 2a + b = 5
------------------------- -
b = 1
a + b = 3
a + 1 = 3
a = 3 - 1
a = 2
f(x) = ax + b
f(x) = 2x + 1