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f(x)=3x-5
f(x+2)=3(x+2)-5=3x-1
f(2x-1)=3(2x-1)-5=6x-8
f(-x+5)=3(-x+5)-5=-3x+10
B.
f(a+2)=f(2a-1)
3(a+2)-5=3(2a-1)-5
a+2=2a-1
-a=3
a=3
2
f(6)=6a+1=4
6a=4-1
6a=3
a=0.5
A.f(x)=0.5 x+1
B.f(-2)=0.5 (-2) + 1 =-1+1 = 0
C.f(2)=0.5(2)+1= 1+1=2
f(-2)=f(2) = 0=2 = 2
D.f(2x-1)=0.5 (2x-1)+1 =x-0.5+1 = x+0.5