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x - ilość 5
y- ilość 4
x+y=12 stąd x=12-y
(5x+4y)/12=4,75 obustronnie *12
5x+4y=57
5*(12-y)+4y=57
60-5y+4y=57
60-y=57 obustronnie +y
60=y+57 obustronnie -57
y=3
x=12-3=9
Zuza miała 9 piątek i 3 czwórki.