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f(x+3)=f(x) + 9.
f(x) = ax + b - wzór szukanej funkcji liniowej
f(3x) = 3ax
f(3x) = 3(ax + b) - 2
f(x + 3) = a(x + 3) + b
f(x + 3) = ax + b + 9
3ax = 3(ax + b) - 2
a(x + 3) + b = ax + b + 9
3ax = 3ax + 3b - 2
ax + 3a + b = ax + b + 9
3b = 2 /:3
b = 2/3
3a = 9 / :3
a = 3
f(x) = 3x + 2/3
Odp: Funkcja liniowa dana jest wzorem: f(x) = 3x + 2/3.