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f(x)=a(x-1)(x-4)
f(3)=a(3-1)(3-4)=-4
-2a=-4
a=2
Postac iloczynowa:
f(x)=2(x-1)(x-4)
2(x²-4x-x+4)=2(x²-5x+4)
Postac ogolna:
f(x)=2x²-10x+8