znajdź pierwiastek wielomiana :
2x (sześcian) - 5x (sześcian) - 8x + 20 = 0
a może tam jest 5x^2 (kwadrat)?
2x^3 - 5x^2 - 8x +20 = 0
x^2(2x-5) - 4(2x - 5) = 0
(2x - 5)(x^2 - 4) = 0
2(x- 5/2)(x-2)(x+2) = 0
x₁= 5/2
x₂ = 2
x₃ = -2
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a może tam jest 5x^2 (kwadrat)?
2x^3 - 5x^2 - 8x +20 = 0
x^2(2x-5) - 4(2x - 5) = 0
(2x - 5)(x^2 - 4) = 0
2(x- 5/2)(x-2)(x+2) = 0
x₁= 5/2
x₂ = 2
x₃ = -2