Znajdź dwie liczby,których suma wynosi 12 i jedna z liczb jest 3 razy mniejsza od drugiej.
9+3=12
x + y = 12
x = 1/3y
1/3y + y = 12
4/3y = 12
y = 9
x = 1/3 * 9
x = 3
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9+3=12
x + y = 12
x = 1/3y
1/3y + y = 12
x = 1/3y
4/3y = 12
x = 1/3y
y = 9
x = 1/3 * 9
y = 9
x = 3