Zmieszano ze sobą 2 roztwory 5 kg trzy procentowego roztworu oraz 1200 g pięcio procentowego roztworu.Oblicz stężenie.
1) mr1=5000g
Cp1=3%
ms1= Cp*mr/100%
ms1= 3*5000/100
ms1=150g
ma- masa wody
ma1= 5000-150=4850g
2) mr2= 1200g
Cp2=5%
ms2=5*1200/100
ms2=60g
ma=1200-60=1140g
3) ms3=60g+150g=210g
ma3=1140+4850=5990g
mr3= 210+5990= 6200g
Cp3=210/6200*100=3,39%
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1) mr1=5000g
Cp1=3%
ms1= Cp*mr/100%
ms1= 3*5000/100
ms1=150g
ma- masa wody
ma1= 5000-150=4850g
2) mr2= 1200g
Cp2=5%
ms2=5*1200/100
ms2=60g
ma=1200-60=1140g
3) ms3=60g+150g=210g
ma3=1140+4850=5990g
mr3= 210+5990= 6200g
Cp3=210/6200*100=3,39%