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dane mr1=100g, c1=20%, mw=25g,
szukane c2
masa subst. rozp. ms jest taka sama przed i poodparowaniu wody
ms1 = mr1*c1/100%
ms2 = mr2*c2/100%
mr1 *c1 = mr2 *c2........mr2 = mr1 - mw = 100g - 25g =75g
c2 = mr1 *c1/mr2 = 100g*20%/75g = 26,67%
Otrzymano r-r o stężeniu c2 = 26,67%
.........................pozdrawiam