Zbiorem wartości funkcji y = -2 + 12x + 1 jest: ?
Wyrażenie - 3(x+ dla x=0
przyjmuje wartość :....?
rozwiąż równanie :
1)
y = -2 x^2 + 12 x + 1
a = - 2 , b = 12, c = 1
p = -b/(2a) = -12/ (-4) = 3
q = -2*3^2 +12*3 + 1 = -2*9 + 36 + 1 = - 18 + 36 + 1 = 19
a = - 2 < 0 - ramiona paraboli skierowane są ku dołowi
zatem zbiór wartości funkcji
ZW = ( - oo; q > = ( -oo ; 19 >
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2)
x = 0
zatem
( 1 - 0)^2 - 3*(0 + p(2))*( 0 - p(2)) =
= 1 - 3* p(2)*( - p(2)) = 1 +3*2 = 1 + 6 = 7
=======================================
3)
x^3 + 4 x^2 - 2 x - 8 = 0
x^2*( x + 4) - 2*( x + 4) = 0
( x + 4)*( x^2 - 2) = 0
( x + 4)*( x - p(2))*( x + p(2)) = 0
x + 4 = 0 lub x - p(2) = 0 lub x + p(2) = 0
x = - 4 lub x = p(2) lub x = - p(2)
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1)
y = -2 x^2 + 12 x + 1
a = - 2 , b = 12, c = 1
p = -b/(2a) = -12/ (-4) = 3
q = -2*3^2 +12*3 + 1 = -2*9 + 36 + 1 = - 18 + 36 + 1 = 19
a = - 2 < 0 - ramiona paraboli skierowane są ku dołowi
zatem zbiór wartości funkcji
ZW = ( - oo; q > = ( -oo ; 19 >
=================================
2)
x = 0
zatem
( 1 - 0)^2 - 3*(0 + p(2))*( 0 - p(2)) =
= 1 - 3* p(2)*( - p(2)) = 1 +3*2 = 1 + 6 = 7
=======================================
3)
x^3 + 4 x^2 - 2 x - 8 = 0
x^2*( x + 4) - 2*( x + 4) = 0
( x + 4)*( x^2 - 2) = 0
( x + 4)*( x - p(2))*( x + p(2)) = 0
x + 4 = 0 lub x - p(2) = 0 lub x + p(2) = 0
x = - 4 lub x = p(2) lub x = - p(2)
=============================================