ZBIOREM ROZWIAZAN NIERÓWNOSCI 3X^ + 2X - 1<0 JEST?
3x² + 2x - 1<0
Δ=2²-4*3*(-1)=4+12=16
√Δ=4
x₁=(-2+4)/6=⅓
x₂=(-2-4)/6=-1
x∈(-1;⅓)
3x²+3x-x-1<0
3x(x+1)-(x+1)<0
(3x-1)(x+1)<0
x=1/3 ∨ x=-1
x∈(-1,1/3)
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3x² + 2x - 1<0
Δ=2²-4*3*(-1)=4+12=16
√Δ=4
x₁=(-2+4)/6=⅓
x₂=(-2-4)/6=-1
x∈(-1;⅓)
3x² + 2x - 1<0
3x²+3x-x-1<0
3x(x+1)-(x+1)<0
(3x-1)(x+1)<0
x=1/3 ∨ x=-1
x∈(-1,1/3)