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[(x+1)+(y-1)]/(y-1)(x+1)=1
[x+y]=(y-1)(x+1)
x+y= yx+y-x-1
x+x+y-y-yx+1=0
2x-yx+1=0
-yx=-1-2x/:(-x)
y=2+1/x, D: x≠0, funkcja dodatnia przechodzi przez punkty np.(1,3), (-1,1)