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d-przekątna
sin30=h/√3 (√3)²=(√3/2)²+a²
½=h/√3 3=¾+a²
2h=√3 a²=3-¾
h=√3/2 a²=9/4
a=3/2
3/2*2=3
6-3=3-dlugosc drugiej podstawy
P=½*h*(a+b)=½*√3/2*(6+3)=√3/4*9=9√3/4 cm²
przekatna z pitagorasa (7.5)²+(√3/2)²=d