Zapisz za pomocą sumy algebraicznej :
(3x1+1)+2(x-1)=
(a-b)-(2a+2b) =
(3x1+1)+2(x-1)= 3x+1+2x-2=5x-1
(a-b)-(2a+2b)= a-b-2a-2b=-a-3b
(3x1+1)+2(x-1)= 3x + 1 + 2x -2 = 5x - 1
(a-b)-(2a+2b) =a -b - 2a - 2b = -a -3b
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(3x1+1)+2(x-1)= 3x+1+2x-2=5x-1
(a-b)-(2a+2b)= a-b-2a-2b=-a-3b
(3x1+1)+2(x-1)= 3x + 1 + 2x -2 = 5x - 1
(a-b)-(2a+2b) =a -b - 2a - 2b = -a -3b