Zapisz w postaci sumy algebraicznej:
a) (x-4)(x+1)²
b) (2x-3)² (x+2)
Odpowiedzi do przykładów : (takie powinny wyjść wyniki)
a)x³-2x²-7x-4
b)4x³-4x²-15x+18
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a) (x-4)(x+1)² = (x-4)(x²+2x+1)=x³-4x²+2x²-8x+x-4=x³-2x²-7x-4
b) (2x-3)² (x+2) = (4x²-12x+9)(x+2)=4x³+8x²-12x²-24x+9x+18=4x³-4x²-15x+18
a)(x-4)(x^{2}+2*x*1+1^{2})=(x-4)(x^{2}+2x+1)=x^{3}+2x^{2}+x-4x^{2}-8x-4=x^{3}-2x^{2}-7x-4
b)(2x-3)^{2}(x+2)=((2x)^{2}-2*2x*3+3^{2})(x+2)=(4x^{2}-12x+9)(x+2)=4x^{3}+8x^{2}-12x^{2}-24x+9x+18=4x^{3}-4x^{2}-15x+18
np.^{2}- do kwadratu