Zapisz w postaci sumy algebraicznej :
a) (x+1)(x+2)(x+3)
b) (x-2)(x+5)(2x-1)
c) (x-4)(x+1)^2
d) (2x-3)^2(x+2)
a) (x+1)(x+2)(x+3)= (x+1)(x²+5x+6)= x³+6x²+11x+6
b) (x-2)(x+5)(2x-1)= (x-2)(2x²+9x-5)= 2x³+5x²-23x+10
c)(x-4)(x+1)²= (x-4)(x²+2x+1)= x³-2x²-7x-4
d)(2x-3)²(x+2)= (4x²-12x+9)(x+2)= 4x³-4x²-15x+18
moim zdaniem powinno być tak :)
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a) (x+1)(x+2)(x+3)= (x+1)(x²+5x+6)= x³+6x²+11x+6
b) (x-2)(x+5)(2x-1)= (x-2)(2x²+9x-5)= 2x³+5x²-23x+10
c)(x-4)(x+1)²= (x-4)(x²+2x+1)= x³-2x²-7x-4
d)(2x-3)²(x+2)= (4x²-12x+9)(x+2)= 4x³-4x²-15x+18
moim zdaniem powinno być tak :)