" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
b) 6-2√3+2√3-2=0
po skróceniu wynosi 4
c) x²√2-4x-x-2√2=0
x²√2-5x-2√2=0
d) 2x√2+x²+4+x√2
(√3+1)(2√3-2)=6-2=4
(x√2+1)(x-2√2)=x²√2-4x+x-2√2=x²√2-3x-2√2
(x+√2)(2√2+x)=2x√2+x²+4+x√2=x²+3x√2+4
(2x+5)² = 4x² + 20x + 25
Przekształć iloczyny na sumy
(∫3+1)(2∫3-2) = 6 - 2∫3 + 2∫3- 2)
(x∫2+1)(x-2∫2) = x²∫2 - 4x + x - 2∫2
(x+∫2)(2∫2+x) = 2∫2x + x² + 4 + x ∫2