Zapisz w postaci potęgi liczby 2
błagam,jutro mam to jako praca semestralna.
(V2)1/3 : (1/32)^-2 * 16^-3 =
2^(1/6) : (2^-5)^-2 * (2^4)^-3=
2^(1/6) : 2^10 * 2^(-12)=
2^(1/6 - 10 -12)=
2^(-21i5/6)
(2^1/2)^1/3 : 32^2 * (2^4)^3
2^1/6: 2^10*2^-12
2^1/6:2^-2
2^-1 5/6
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(V2)1/3 : (1/32)^-2 * 16^-3 =
2^(1/6) : (2^-5)^-2 * (2^4)^-3=
2^(1/6) : 2^10 * 2^(-12)=
2^(1/6 - 10 -12)=
2^(-21i5/6)
(2^1/2)^1/3 : 32^2 * (2^4)^3
2^1/6: 2^10*2^-12
2^1/6:2^-2
2^-1 5/6