Question

Zapisz w postaci jednej potęgi:

Answer 1

8^-7 * 8^-4 = 8^{-7-4} = 8^-11

a^12 * b^8 = a^4 * a^8 * b^8 = a^4 *(ab)^8

3^-4 : 3^-2 = 3^{-4 - (-2)} = 3^-2

(0,6)^7 * (-0,09)^7 = [0,6 *(-0,09)]^7 = (-0,054)^7

4^12 * 7^12 = (4 * 7)^12 = 28^12

(5^-3)^4 * 5^7 : 5^-4 = 5^-12 * 5^7 : 5^-4 = 5^-5 : 5^-4 = 5^-1

20^-9 : 4^-9 = (20/4)^-9 = 5^-9

(0,054)^-12 : (-0,6)^-12 = (-0,054/0,6)^-12 = (-0,09)^-12 = 0,09^-12

4^2 : 8^4 * 2^-5 = (2^2)^2 : (2^3)^4 * 2^-5 = 2^4 : 2^12 * 2^-5 = 2^{4-12} * 2^-5 =
2^-8 * 2^-5 = 2^-13
 = 2^-13