Zapisz w notacji wykładniczej:
a)12345=
b)1212,12=
c)6000000=
d)0,123456=
e)0,000001=
f)0,0002345=
a) 12345=1,2345 * 10⁴
b) 1212,12=1,21212 * 10³
c)6000000=6 * 10⁶
d)0,123456=1,23456 * 10⁻¹
e)0,000001=1 * 10⁻⁵
f)0,0002345=2,3 * 10⁻⁴
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a) 12345=1,2345 * 10⁴
b) 1212,12=1,21212 * 10³
c)6000000=6 * 10⁶
d)0,123456=1,23456 * 10⁻¹
e)0,000001=1 * 10⁻⁵
f)0,0002345=2,3 * 10⁻⁴