Question

Zapisz w jak najprostszej postaci:

d) -(3c-2)(c-1)-c(c-2)=

e ) 2(3a^2-1)-(a+2)(a+2)=

f) 5^2(x^2+1)-(x^2-2)(x^2+3)=

Answer 1

d)   -(3c-2)(c-1)-c(c-2)= -3c+2*(c-1)-c²+2c=-3c+2c-2-c²+2c = c-2-c²

 

e )   2(3a^2-1)-(a+2)(a+2)=6a²-2-a-2*(a+2) = 6a²-2-a-2a-4=6a²-6-3a

 

f)     5^2(x^2+1)-(x^2-2)(x^2+3)=25(x²+1)-(x²-2)(x²+3) = 25x²+25-x²+2*(x²+3) = 25x² +25-x²+2x²+6 = 26x²+31

Answer 2

d)=

delta=49-40=9

pierwiastek z delty = 3

c1=1

c2=0,4

 

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