zapisz w jak najprostszej postaci
a) (2x-6)²-(2x-6)
b) (3x+2)²-(3x+2)∙(3x-2)
a) (2x-6)²- (2x-6) = (2x)²- 2*2x*6+6²- (2x)²-2*2x*6+6²= 4x² - 24x+36-4x²-24x+36=72
b) (3x+2)²-(3x+2)∙(3x-2)= (3x)² + 2*3x*2 +2²- 9x²-4=9x²+12x+4-9x²-4=12x
*razy
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a) (2x-6)²- (2x-6) = (2x)²- 2*2x*6+6²- (2x)²-2*2x*6+6²= 4x² - 24x+36-4x²-24x+36=72
b) (3x+2)²-(3x+2)∙(3x-2)= (3x)² + 2*3x*2 +2²- 9x²-4=9x²+12x+4-9x²-4=12x
*razy