Zapisz w jak najprostszej postaci. ( taki znaczek ^ oznacz do potęgi drugiej kwadrat)
a) 6a^- 3c+2a^-5c-10a^+c=
b) 2(5+2x)*(3x-2)=
c) (5+2x)*(3x-2)=
d) 2x(4x-1)-(x-2)*(x+2)=
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
d)2x(4x-1)-(x-2)*(x+2)=8x^-2x-x^+2x-2x-4=7x^-2x-4
c)(5+2x)*(3x-2)=15x-10+6x^-4x=11x-10+6x^
b)2(5+2x)*(3x-2)=(10+4x)*(3x-2)=30x-20+12x^-8x=22x-20+12x^
a)6a^-3c+2a^-5c-10a^+c=8a^-10a^-8c+c=-2a^-7c