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x+2x-z
3x-z
b) a-b+a
2a-b
c) a-[b-a-b]
a-b+a+b
2a
Chyba taak. :)
b)-(-a)+(-b+a)=a-b+a=2a-b
c)a-[b-(a+b)]=a-[b-a-b]=a-b+a+b=2a
b) -(-a)+(-b+a)=2-b+a=2a-b
c) a-[b-(a+b)]=a-(b-a-b)=a-b+a+b=2a