Zapisz sume w postaci iloczynu
4a(x+y)-x-y
x(1-pierwiastek z trzech)-y(pierwiastek z trzech-1)
(3-p)r+2(p-3)
proszę o pomoc
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4a(x+y)-x-y = 4a(x+y) -(x+y) = (x+y)(4a-1)
x(1-√3)-y(√3-1) = x(1-√3) - (-y)(1-√3) = (1-√3)(x+y)
(3-p)r + 2(p-3) = -(p-3)r + 2(p-3) = (p-3)(-r+2)