zapisz pole(załącznik)
a)
(x+5)(x+2)+2x(x-1)= 3x²+5x+10
b)
(x+1)(2x+3)+(x-1)(x-1)=
3x²+3x+4
c)
2(x-1)(x+2)+[(3x-1)-2(x-1)](x+2)-(x+3)=
2x²+4x-2
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a)
(x+5)(x+2)+2x(x-1)= 3x²+5x+10
b)
(x+1)(2x+3)+(x-1)(x-1)=
3x²+3x+4
c)
2(x-1)(x+2)+[(3x-1)-2(x-1)](x+2)-(x+3)=
2x²+4x-2