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b₁=3*1 b₁=3
b₂=3*2 b₂=6
b₃=3*3 b₃=9
b)dn=n^n
d₁=1¹ d₁=1
d₂=2² d₂=4
d₃=3³ d₃=27
c) en=(5n-3)/(n+1)
e₁=(5*1-3)/1+1) e₁=1
e₂=(5*2-3)/(2+1) e₂=7/3
e₃=(5*3-3)/(3+1) e₃=3
d) fn=6-n²
f1=6-1² f₁=5
f₂=6-2² f₂=4
f₃=6-3³ f₃=-3