Zapisz bez użycia wartości bezwzględnej |3√2-π|+|3^(-2)-2^(-2) |-|π√11|
Z góry dziękuję:)
3√2-π - 3^(-2) + 2^(-2) - π + √11 =
= 4.24 - 3.14 - 1/9 + 1/4 - 3.14 + 3.31 =
= 4.24 - 3.14 - 0.11 + 0.25 - 3.14 + 3.31 =
= 7.69
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3√2-π - 3^(-2) + 2^(-2) - π + √11 =
= 4.24 - 3.14 - 1/9 + 1/4 - 3.14 + 3.31 =
= 4.24 - 3.14 - 0.11 + 0.25 - 3.14 + 3.31 =
= 7.69