Zamień sumę na iloczyn :
a) 2y(x+y)-y-x=
b)x(x-1)-2(1-x)=
c)(x+y) <do potęgi 2 > +2 (x+y)=
e)a(a-1)-4(1-a)=
f)3z(x -5) + (5-z) =
g)3b(2-4) -(4-b)
h)5(x-7)+10y(7-x) =
i) 3(x+y) + (x+y) < do potegi 2) =
j) 5(a-b) <do potęgi 2 > - (a-b) =
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Zamień sumę na iloczyn :
a) 2y(x+y)-y-x=
= 2y(x +y) -1(x +y) =
= (x +y)*(2y -1)
b)x(x-1)-2(1-x)=
x(x -1) +2(x -1) =
= (x -1)*(x +2)
c)(x+y) <do potęgi 2 > +2 (x+y)=
(x +y)² + 2(x +y) =
= (x+y)(x+y) +2(x +y) =
= (x +y)*(x +y +2)
e)a(a-1)-4(1-a)=
a(a -1) + 4(a -1)=
= (a -1)*(a +4)
f)3z(x -5) + (5-z) =
= 3z(x -5) -1(z -5) =
= (x-5)*(3z -1)
g)3b(2-4) -(4-b)=
= tutaj jest coś nie tak brak w pierwszym nawiasie b
h)5(x-7)+10y(7-x) =
= 5(x -7) -10y( x -7) =
= (x-7)*(5 -10y) =
=5*(1 -2y)*(x -7)
i) 3(x+y) + (x+y) < do potegi 2) =
= 3(x +y) + (x +y)(x+y) =
= (x +y)(3 +x +y)
j) 5(a-b) <do potęgi 2 > - (a-b) =
= 5(a -b)(a -b) - 1(a-b) =
= (a -b)(5a -5b -1)