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postać iloczynowa --> f(x) = 1/4(x+2)^2
kanoniczna f(x) = 1/4(x+2)^2
przy f(x)= 3x^2-6x
Δ=36
= 0
= 2
więc f(x) = 3x(x-2)
q=-3 więc f(x) = 3(x-1)^2-3
Liczę na naj!!