" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
zalozenie:
-2x²+5x+12≥0
-2x²+8x-3x+12≥0
2x(4-x) - 3(x-4) ≥0
(x-4)(2x-3)≥0
m.z. x=3/2 v x=4
D=<3/2, 4>
|-2x²+5x+12| > (6-x)²
-2x²+5x+12 > 36-12x+x²
-3x²+17x-24 > 0
Δ=289-4*3*24 = 1
x=(-17-1)/(-6) = 3 v x=(-17+1)/(-6)=8/3
______8/3_____3______>
_ _ 0 + + 0 _ _
Odp. x∈(2²/₃ , 3)